Search any question & find its solution
Question:
Answered & Verified by Expert
What is the equation for the equilibrium constant $\left(K_c\right)$ for the following reaction?
$\frac{1}{2} A(g)+\frac{1}{3} B(g) \stackrel{T(K)}{\rightleftharpoons} \frac{2}{3} C(g)$
Options:
$\frac{1}{2} A(g)+\frac{1}{3} B(g) \stackrel{T(K)}{\rightleftharpoons} \frac{2}{3} C(g)$
Solution:
1905 Upvotes
Verified Answer
The correct answer is:
$K_c=\frac{[C]^{2 / 3}}{[A]^{1 / 2}[B]^{1 / 3}}$
$\begin{aligned} & \frac{1}{2} A(g)+\frac{1}{3} B(g) \stackrel{T(K)}{\rightleftharpoons} \frac{2}{3} C(g) \\ & \text { Equilibrium constant, } K_c=\frac{\text { Rate product }}{\text { Rate of reactant }} \\ & \qquad K_c=\frac{[C]^{2 / 3}}{[A]^{1 / 2}[B]^{1 / 3}}\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.