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What is the oxidation number of carbon in glucose?
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The correct answer is:
Zero
$\begin{array}{l}
\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6} \\
6 \mathrm{x}+12-12=0
\end{array}$
C has oxidation number $=0$
\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6} \\
6 \mathrm{x}+12-12=0
\end{array}$
C has oxidation number $=0$
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