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What is the oxidation number of Carbon in $\mathrm{K}_{2} \mathrm{C}_{2} \mathrm{O}_{4}$?
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Verified Answer
The correct answer is:
$+3$
$\mathrm{K}_{2} \mathrm{C}_{2} \mathrm{O}_{4} \Rightarrow(1 \times 2)+(\mathrm{x} \times 2)+(-2 \times 4)$
$=2+2 x-8$
$=2 x-6$
$\therefore x=+3$
$\therefore$ The oxidation number of $C=+3$
$=2+2 x-8$
$=2 x-6$
$\therefore x=+3$
$\therefore$ The oxidation number of $C=+3$
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