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What is the oxidation number of $\mathrm{Pt}$ in $\mathrm{PtCl}_6^{2-}$ ?
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The correct answer is:
+4
$\begin{array}{ll} & \mathrm{PtCl}_6^{2-}: \\ & x+(-1 \times 6)=-2 \\ \therefore \quad & x=+4\end{array}$
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