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What is the probability that at least two persons out of a group of three persons were born in the same month (disregard year)?
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Verified Answer
The correct answer is:
$\frac{17}{72}$
Probability that no one born in the same month $=\frac{12 \times 11 \times 10}{12 \times 12 \times 12}$
Probability that atleast two are born in same month
$=1-\frac{12 \times 11 \times 10}{12 \times 12 \times 12}$
$=\frac{144-110}{144}=\frac{17}{72}$
Probability that atleast two are born in same month
$=1-\frac{12 \times 11 \times 10}{12 \times 12 \times 12}$
$=\frac{144-110}{144}=\frac{17}{72}$
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