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What is the quantity of glucose obtained when $68.4 \mathrm{~g}$ of sucrose is hydrolyzed in laboratory under ideal condition ? (molar mass of sucrose $=342 \mathrm{~g} \mathrm{~mol}^{-1}$ )
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The correct answer is:
$36 \cdot 0 \mathrm{~g}$
$342 \mathrm{~g}$ of sucrose gives $180 \mathrm{~g}$ of glucose.
$\therefore 68.4 \mathrm{~g}$ of sucrose gives $\frac{180 \times 68.4}{342}=36 \mathrm{~g}$ of glucose.
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