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What is the quantity of water required to obtain one mole of glucose from one mole of sucrose by acid hydrolysis?
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The correct answer is:
$18.0 \mathrm{~g}$
$\begin{aligned} & \mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}+\mathrm{H}_2 \mathrm{O} \stackrel{\mathrm{H}^{+}}{\longrightarrow} \mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6+\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6 \\ & \text { Sucrose glucose fructose } \\ & 1 \mathrm{~mol} \quad 1 \mathrm{~mol} \\ & \text { Mole of } \mathrm{H}_2 \mathrm{O}=\text { Mole of glucose } \\ & \end{aligned}$
$\frac{w}{18}=1$
$\because w=18 \mathrm{~g}$
$\frac{w}{18}=1$
$\because w=18 \mathrm{~g}$
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