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What is the self inductance of a coil in which an induced emf of $2 \mathrm{~V}$ is set up, when the current is changing at the rate of $4 \mathrm{As}^{-1}$
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The correct answer is:
$0.5 \mathrm{H}$
Induced emf, $e=\frac{L d i}{d t}$, here, $e=2 \mathrm{~V}, \frac{d i}{d t}=4 \mathrm{As}^{-1}$
$\begin{aligned}
\Rightarrow \quad & 2=L \times 4 \\
L &=\frac{2}{4}=0.5 \mathrm{H}
\end{aligned}$
$\begin{aligned}
\Rightarrow \quad & 2=L \times 4 \\
L &=\frac{2}{4}=0.5 \mathrm{H}
\end{aligned}$
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