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What is the value of percent atom economy when an organic compound of formula weight $75 \mathrm{u}$ is obtained from reactants having sum formula weight $225 \mathrm{u}$ ?
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Verified Answer
The correct answer is:
$33.3$
$\%$ atom economy
$=\frac{\text { Formula weight of the desired product }}{\text { Sum of formula weight of all the reactants }} \times 100$
used in the reaction
$\% \text { atom economy }=\frac{75}{225} \times 100=33.3$
$=\frac{\text { Formula weight of the desired product }}{\text { Sum of formula weight of all the reactants }} \times 100$
used in the reaction
$\% \text { atom economy }=\frac{75}{225} \times 100=33.3$
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