Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
What is the value of $\sin \left(\frac{5 \pi}{12}\right)$ ?
MathematicsTrigonometric Ratios & IdentitiesNDANDA 2008 (Phase 1)
Options:
  • A $\frac{\sqrt{3}+1}{2}$
  • B $\frac{\sqrt{6}+\sqrt{2}}{4}$
  • C $\frac{\sqrt{3}+\sqrt{2}}{4}$
  • D $\frac{\sqrt{6}+1}{2}$
Solution:
1843 Upvotes Verified Answer
The correct answer is: $\frac{\sqrt{6}+\sqrt{2}}{4}$
$\begin{aligned} & \sin \frac{5 \pi}{12}=\sin 75^{\circ} \\ &=\sin \left(45^{\circ}+30^{\circ}\right) \\ &=\sin 45^{\circ} \cos 30^{\circ}+\cos 45^{\circ} \sin 30^{\circ} \\ &=\frac{1}{\sqrt{2}} \cdot \frac{\sqrt{3}}{2}+\frac{1}{\sqrt{2}} \cdot \frac{1}{2}=\frac{1}{\sqrt{2}}\left(\frac{\sqrt{3}+1}{2}\right) \\ &=\frac{\sqrt{3}+1}{2 \sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{6}+\sqrt{2}}{4} \end{aligned}$

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.