Search any question & find its solution
Question:
Answered & Verified by Expert
What is the van't Hoff factor of Ferric Sulphate (Assume $100 \%$ ionization)
Options:
Solution:
2270 Upvotes
Verified Answer
The correct answer is:
$5$
Ferric sulphate $=\mathrm{Fe}_2\left(\mathrm{SO}_4\right)_3$
$\mathrm{Fe}_2\left(\mathrm{SO}_4\right)_3 \rightarrow 2 \mathrm{Fe}^{3+}+3 \mathrm{SO}_4{ }^{2-}$ (complete ionization)
$\Rightarrow \quad$ van't Hoff factor $=i=2+3=5$.
$\mathrm{Fe}_2\left(\mathrm{SO}_4\right)_3 \rightarrow 2 \mathrm{Fe}^{3+}+3 \mathrm{SO}_4{ }^{2-}$ (complete ionization)
$\Rightarrow \quad$ van't Hoff factor $=i=2+3=5$.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.