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What is 'X' in the following sequence?
Ar. $\mathrm{N}_2 \mathrm{Cl} \xrightarrow[\mathrm{KCN}]{\mathrm{CuCN}} \mathrm{Z} \xrightarrow{\mathrm{H}. \mathrm{OH}} \mathrm{Y} \xrightarrow[\Delta]{\text { soda-lime }} \mathrm{X}$
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Ar. $\mathrm{N}_2 \mathrm{Cl} \xrightarrow[\mathrm{KCN}]{\mathrm{CuCN}} \mathrm{Z} \xrightarrow{\mathrm{H}. \mathrm{OH}} \mathrm{Y} \xrightarrow[\Delta]{\text { soda-lime }} \mathrm{X}$
Solution:
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Verified Answer
The correct answer is:
Benzene
The reaction sequence is as follows:
\(\mathrm{ArN}_2 \mathrm{Cl} \xrightarrow[\text { Sandmeyer's reaction }]{\mathrm{CuCNKCN}}\mathrm{ArCN} \xrightarrow{\mathrm{H} . \mathrm{OH}} \underset{\text{benzoic acid}}{\mathrm{C}_6 \mathrm{H}_5 \mathrm{COOH}}\xrightarrow[\text { decarboxylation }]{\Delta \text {, sodalime }} \underset{\text { benzene }}{\mathrm{C}_6 \mathrm{H}_6}\)
\(\mathrm{ArN}_2 \mathrm{Cl} \xrightarrow[\text { Sandmeyer's reaction }]{\mathrm{CuCNKCN}}\mathrm{ArCN} \xrightarrow{\mathrm{H} . \mathrm{OH}} \underset{\text{benzoic acid}}{\mathrm{C}_6 \mathrm{H}_5 \mathrm{COOH}}\xrightarrow[\text { decarboxylation }]{\Delta \text {, sodalime }} \underset{\text { benzene }}{\mathrm{C}_6 \mathrm{H}_6}\)
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