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What product is obtained when alkyl halides react with metallic sodium in presence of dry ether?
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Alkanes with double the number of carbon atoms as in alkyl halide.
Wurtz reaction:
This involves coupling of two identical molecules of alkyl halide upon treatment with $\mathrm{Na}$ metal in presence of dry ether to give alkanes with double the number of carbon atoms as in alkyl halide as follows:
$\mathrm{R}-\mathrm{X} \stackrel{\mathrm{Na} / \text { dry ether }}{\longrightarrow} \mathrm{R}-\mathrm{R}+\mathrm{NaX}$
This involves coupling of two identical molecules of alkyl halide upon treatment with $\mathrm{Na}$ metal in presence of dry ether to give alkanes with double the number of carbon atoms as in alkyl halide as follows:
$\mathrm{R}-\mathrm{X} \stackrel{\mathrm{Na} / \text { dry ether }}{\longrightarrow} \mathrm{R}-\mathrm{R}+\mathrm{NaX}$
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