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Question: Answered & Verified by Expert
What volume of O2 measured at standard conditions will be formed by the action of 100 mL of 0.5 KMnO4 on hydrogen peroxide in an acidic solution?
ChemistrySome Basic Concepts of ChemistryNEET
Options:
  • A 0.12 litre
  • B 0.28 litre
  • C 0.56 litre
  • D 1.12 litre
Solution:
2297 Upvotes Verified Answer
The correct answer is: 0.28 litre
Here H2O2 on reaction with KMnO4 gives O2 so
Meq. of O2=Meq of KMnO4=100×0.5
w8×1000=50 (equivalent weight of oxygen is 8)
So wO2=0.4 g
So VO2=22.4×0.432=0.28 litre.

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