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What will be the final product in the following reaction sequence -
$$
\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CN} \stackrel{\mathrm{H}^{+} / \mathrm{H}_2 \mathrm{O}}{\longrightarrow} \mathrm{A} \stackrel{\mathrm{NH}_3}{\longrightarrow} \mathrm{B} \stackrel{\mathrm{NaOBr}}{\longrightarrow} \mathrm{C}
$$
Options:
$$
\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CN} \stackrel{\mathrm{H}^{+} / \mathrm{H}_2 \mathrm{O}}{\longrightarrow} \mathrm{A} \stackrel{\mathrm{NH}_3}{\longrightarrow} \mathrm{B} \stackrel{\mathrm{NaOBr}}{\longrightarrow} \mathrm{C}
$$
Solution:
2486 Upvotes
Verified Answer
The correct answer is:
$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NH}_2$
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