What will be the p H of a solution by mtextxing 40 m L of 0.1 M H C l with 10 m L of 0.45 M N a O H ?

Question

What will be the p H of a solution by mtextxing 40 m L of 0.1 M H C l with 10 m L of 0.45 M N a O H ?, 12, 10, 8, 6

MARKS App · Accepted Answer

40 m L o f 0 . 1 M H C l = 0.1 1000 × 40 = 0.004 m o l e 10 m L o f 0.45 M N a O H = 0.45 1000 × 10 = 0.0045 m o l e ∴ N a O H left unused = 0.0005 m o l e Volume of solution = 50 m L ∴ M o l a r i t y o f N a O H = 0.0005 50 × 1000 = 0.01 M Or O H - = 10 - 2 o r H + = 10 - 12 p H = 12

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