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What will be the pH of a solution formed by mixing 40 of 0.1 M HCl with 10 of 0.45 M NaOH?
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Verified Answer
The correct answer is:
12
Number of moles of HCl
Number of moles of NaOH
Remaining moles of NaOH after neutralization = 0.0045 – 0.004 = 0.0005
Molarity of
So pOH
So pH = 14 – 2 = 12
Number of moles of NaOH
Remaining moles of NaOH after neutralization = 0.0045 – 0.004 = 0.0005
Molarity of
So pOH
So pH = 14 – 2 = 12
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