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Question: Answered & Verified by Expert
What will be the stress at -20 °C , if a steel rod with a cross-sectional area of 150 mm2 is stretched between two fixed points? The tensile load at 20 °C is 5000 N. (Assume α=11.7 ×10-6 °C-1 and Y=200 ×1011N m-2 )
PhysicsThermal Properties of MatterJEE Main
Options:
  • A 12.7 ×106 N m-2
  • B 84.2 ×106 N m-2
  • C 127 ×106 N m-2
  • D 0.842 ×106 N m-2
Solution:
1310 Upvotes Verified Answer
The correct answer is: 127 ×106 N m-2
Let L = free length at 0 °C

L0= final stretched length in each case.

L1 and L2 are free length at +20 °C and - 20 °C respectively.




We know s2=s1+2αLΔT

Here, s1 and s2 are load deformation.

F2LAY=F1LAY+2αLΔT

σ2=F2A=F1A+2αΔTY=5000150 ×10-6+2 11.7 ×10-6 20 2 ×1011

=127 ×106 N m-2

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