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When a charge of $20 \mathrm{C}$ is taken from one point to another separated by a distance of $0.2 \mathrm{~m}$, work of $2 \mathrm{~J}$ is required to be done.
What is the potential difference between the two points?
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What is the potential difference between the two points?
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1636 Upvotes
Verified Answer
The correct answer is:
$0.1 \mathrm{~V}$
Charge, $q=20 \mathrm{C}$
$$
\begin{aligned}
d & =0.2 \mathrm{~m} \\
W & =2 \mathrm{~J}
\end{aligned}
$$
Potential difference, $V=\frac{W}{q}$
$$
=\frac{2}{20}=0.1 \mathrm{~V}
$$
$$
\begin{aligned}
d & =0.2 \mathrm{~m} \\
W & =2 \mathrm{~J}
\end{aligned}
$$
Potential difference, $V=\frac{W}{q}$
$$
=\frac{2}{20}=0.1 \mathrm{~V}
$$
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