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Question: Answered & Verified by Expert
When a charge of $20 \mathrm{C}$ is taken from one point to another separated by a distance of $0.2 \mathrm{~m}$, work of $2 \mathrm{~J}$ is required to be done.
What is the potential difference between the two points?
PhysicsElectrostaticsAP EAMCETAP EAMCET 2020 (22 Sep Shift 2)
Options:
  • A $2 \times 10^{-2} \mathrm{~V}$
  • B $4 \times 10^{-4} \mathrm{~V}$
  • C $8 \mathrm{~V}$
  • D $0.1 \mathrm{~V}$
Solution:
1636 Upvotes Verified Answer
The correct answer is: $0.1 \mathrm{~V}$
Charge, $q=20 \mathrm{C}$
$$
\begin{aligned}
d & =0.2 \mathrm{~m} \\
W & =2 \mathrm{~J}
\end{aligned}
$$

Potential difference, $V=\frac{W}{q}$
$$
=\frac{2}{20}=0.1 \mathrm{~V}
$$

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