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When a charged particle moving with velocity $\vec{v}$ is subjected to a magnetic field of induction $\vec{B}$, the force on it is non-zero. This implies that:
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Verified Answer
The correct answer is:
angle between can have any value other than zero and $180^{\circ}$
$$
\begin{aligned}
\vec{F} & =q(\vec{V} \times \vec{B}) \\
& =q v B \sin \theta
\end{aligned}
$$
Therefore when $\theta=0^{\circ}$ or $\theta=180^{\circ}$
$$
F=0
$$
\begin{aligned}
\vec{F} & =q(\vec{V} \times \vec{B}) \\
& =q v B \sin \theta
\end{aligned}
$$
Therefore when $\theta=0^{\circ}$ or $\theta=180^{\circ}$
$$
F=0
$$
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