When a magnet is suspended at an angle 30 ° from the magnetic meridian, it makes an angle 45 o with horizontal. What will be the actual angle of dip?

Question

When a magnet is suspended at an angle 30 ° from the magnetic meridian, it makes an angle 45 o with horizontal. What will be the actual angle of dip?, tan - 1 ⁡ 3 2, tan - 1 ⁡ 3, 45 o, 30 o

MARKS App · Accepted Answer

tan - 1 ⁡ 3 2 Given deviation from magnetic meridian α = 30 o and apparent dip ϕ ′ = 45 ° Then, tan ⁡ ϕ ′ = tan ⁡ ϕ cos ⁡ α tan ⁡ 45 o = tan ⁡ ϕ cos ⁡ 30 o ϕ = tan - 1 ⁡ 3 2

Search any question & find its solution

Looking for more such questions to practice?