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When a metal conductor connected to left gap of a meter bridge is heated, the balancing point
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shifts towards right
We know that, resistance of unknown wire can be determined by using meter bridge as
$$
\frac{R}{S}=\frac{l}{100-l} \Rightarrow S=\frac{R(100-l)}{l}
$$
where $R=$ known resistance, $l=$ balancing length and $S=$ unknown resistance.
When a metal conductor of resistance $R$ connected to left gap is heated, then its resistance increases i.e. $R$ increases. Hence, from Eq. (i), we see that when $R$ will increase, then $(100-l)$ will decrease also, i.e $l$ will increase. Therefore, balancing point will shift towards right.
$$
\frac{R}{S}=\frac{l}{100-l} \Rightarrow S=\frac{R(100-l)}{l}
$$
where $R=$ known resistance, $l=$ balancing length and $S=$ unknown resistance.
When a metal conductor of resistance $R$ connected to left gap is heated, then its resistance increases i.e. $R$ increases. Hence, from Eq. (i), we see that when $R$ will increase, then $(100-l)$ will decrease also, i.e $l$ will increase. Therefore, balancing point will shift towards right.
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