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When phenol is treated with $\mathrm{CHCl}_3$ and $\mathrm{NaOH}$, the product formed is:
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salicylaldehyde
When phenol is treated with $\mathrm{CHCl}_3$ and $\mathrm{NaOH}$ the product formed is salicylaldehyde, this reaction is known as Reimer-Tiemann reaction.
In this reaction chloroform first reacts with sodium hydroxide toproduce dichlorocarbene which is the intermediate of this reaction.
In this reaction chloroform first reacts with sodium hydroxide toproduce dichlorocarbene which is the intermediate of this reaction.
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