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Question: Answered & Verified by Expert
Which of the following statement is incorrect?
Chemistrys Block ElementsJEE MainJEE Main 2022 (28 Jul Shift 1)
Options:
  • A Low solubility of LiF in water is due to its small hydration enthalpy.
  • B KO2 is paramagnetic.
  • C Solution of sodium in liquid ammonia is conducting in nature.
  • D Sodium metal has higher density than potassium metal
Solution:
2674 Upvotes Verified Answer
The correct answer is: Low solubility of LiF in water is due to its small hydration enthalpy.

Due to the small size of Li+ ion and F-ions, the lattice energy of LiF is very high. LiF is covalent in nature. Therefore, LiF is insoluble in water.

KO2  has 1 unpaired electron in π2p Molecular orbital of O2- . Therefore, it is Paramagnetic.

 Lithium has lesser atomic weight than sodium. So, lithium has lesser density than sodium. But in the case of 'K' and 'Na', d-orbitals present in Potassium, which increases the volume of 'K'.

Solution of sodium in liquid ammonia is conducting in nature, due to presence of free electron.

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