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Which of the following statement is not true for hydrolysis of $\mathrm{XeF}_6$ ?
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Verified Answer
The correct answer is:
It is a redox reaction.
(c) : Hydrolysis of $\mathrm{XeF}_6$ is not a redox reaction. $\mathrm{XeF}_6$ reacts violently with water, but slow hydrolysis by atmospheric moisture gives highly explosive solid, $\mathrm{XeO}_3$.
$\mathrm{XeF}_{6(s)}+3 \mathrm{H}_2 \mathrm{O}_{(l)} \longrightarrow \mathrm{XeO}_{3(s)}+6 \mathrm{HF}_{(a q)}$
Partial hydrolysis of $\mathrm{XeF}_6$ yields $\mathrm{XeOF}_4$ and
$\begin{aligned}
& \mathrm{XeO}_2 \mathrm{~F}_2 \\
& \mathrm{XeF}_6+\mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{XeOF}_4+2 \mathrm{HF} \\
& \mathrm{XeF}_6+2 \mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{XeO}_2 \mathrm{~F}_2+4 \mathrm{HF}
\end{aligned}$
$\mathrm{XeF}_{6(s)}+3 \mathrm{H}_2 \mathrm{O}_{(l)} \longrightarrow \mathrm{XeO}_{3(s)}+6 \mathrm{HF}_{(a q)}$
Partial hydrolysis of $\mathrm{XeF}_6$ yields $\mathrm{XeOF}_4$ and
$\begin{aligned}
& \mathrm{XeO}_2 \mathrm{~F}_2 \\
& \mathrm{XeF}_6+\mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{XeOF}_4+2 \mathrm{HF} \\
& \mathrm{XeF}_6+2 \mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{XeO}_2 \mathrm{~F}_2+4 \mathrm{HF}
\end{aligned}$
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