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Question: Answered & Verified by Expert
Which of the following statements is correct?
MathematicsDefinite IntegrationJEE Main
Options:
  • A If fx is an odd function, then gx=axftdt is an even function.
  • B If fx is an odd function, then gx=axftdt is also odd.
  • C If fx is a periodic function, then gx=axftdt is also periodic.
  • D If fx is periodic, then gx=axftdt is always non - periodic.
Solution:
1275 Upvotes Verified Answer
The correct answer is: If fx is an odd function, then gx=axftdt is an even function.
As, gx=0xftdt
g-x=0-xftdt
Put t=-u
dt=-du
g-x=-0xf-udu
0xfudu
(as f x is odd)
g-x=gx
Hence, gx is even.
Also, Consider gx=0xcos2tdt
gx=x2+sin2x4
Which is non - periodic even though y=cos2x is periodic
Also, if gx=0xcostdt
Then, gx=sinx, which is periodic.

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