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Which of the following system in an octahedral complex has maximum unpaired electrons?
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Verified Answer
The correct answer is:
$d^7$ (high spin)
\(\begin{array}{|c|c|}
\hline & \begin{array}{c}
\text { Unpaired } \\
\text { electrons }
\end{array} \\
\hline \begin{array}{c}
d^4 \text { (low spin) } \\
-16
\end{array} & 2 \\
\hline \begin{array}{c}
d^7 \text { (high } \\
\text { spin) }-1
\end{array} & 3 \\
\hline \begin{array}{c}
d^9 \text { (high } \\
\text { spin) }-1
\end{array} & 1 \\
\hline
\end{array}\)
$\therefore d^7$ (high spin) system has maximum unpaired electrons.
\hline & \begin{array}{c}
\text { Unpaired } \\
\text { electrons }
\end{array} \\
\hline \begin{array}{c}
d^4 \text { (low spin) } \\
-16
\end{array} & 2 \\
\hline \begin{array}{c}
d^7 \text { (high } \\
\text { spin) }-1
\end{array} & 3 \\
\hline \begin{array}{c}
d^9 \text { (high } \\
\text { spin) }-1
\end{array} & 1 \\
\hline
\end{array}\)
$\therefore d^7$ (high spin) system has maximum unpaired electrons.
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