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Question: Answered & Verified by Expert
Which one of the following alkenes when treated with HCl yields majorly an anti Markovnikov product?
ChemistryHydrocarbonsJEE MainJEE Main 2019 (08 Apr Shift 2)
Options:
  • A CH3O-CH=CH2
  • B Cl-CH=CH2
  • C H2N-CH=CH2
  • D F3C-CH=CH2
Solution:
1576 Upvotes Verified Answer
The correct answer is: F3C-CH=CH2

Markovnikov’s product is formed when a stable carbocation is formed on the more substituted carbon.

In CF3-CH=CH2, the carbocation formed will be destabilized by strong -I group of CF3. Hence, the Anti-Markovnikov’s product will be formed.

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