Which one of the following aqueous solutions will exhibit highest elivation in boiling point?

Question

Which one of the following aqueous solutions will exhibit highest elivation in boiling point?, 0.05 M glucose (non ionisable), 0.01 M K N O 3 (50 % ionisable), 0.015 M Urea (non ionisable), 0.01 M N a 2 S O 4 (75 % ionisable)

MARKS App · Accepted Answer

Boiling point = T 0 s o l v e n t + Δ T b e l e v a t i o n i n b . p . Δ T b = m i K b where, m is the molality ≈ m o l a r i t y If n is number of species formed after dissociation i, the vant Hoff factor = 1 + n - 1 α K b = molal elevation constant. Thus Δ T b ∝ i Assume 100% ionization 1 m i N a 2 S O 4 = 0.01 1 + 3 - 1 0.75 = 0.025 2 m i K N O 3 = 0.01 × 1 + 2 - 1 0.50 = 0.015 3 m i u r e a = 0.015 4 m i g l u c o s e = 0.05

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