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Question:
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Which one of the following equations has no solution?
Options:
Solution:
1478 Upvotes
Verified Answer
The correct answer is:
$\operatorname{cosec} \theta \cdot \sec \theta=1$
By option (c),
$\operatorname{cosec} \theta \cdot \sec \theta=1$
$\sin \theta \cos \theta=1$
$2 \sin \theta \cos \theta=2$
$\sin 2 \theta=2$
As we know that range of $\sin x$ is $[-1,1]$.
Hence, this equation has no solution.
$\operatorname{cosec} \theta \cdot \sec \theta=1$
$\sin \theta \cos \theta=1$
$2 \sin \theta \cos \theta=2$
$\sin 2 \theta=2$
As we know that range of $\sin x$ is $[-1,1]$.
Hence, this equation has no solution.
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