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Question: Answered & Verified by Expert
Which one of the following has an optical isomer?
ChemistryCoordination CompoundsVITEEEVITEEE 2018
Options:
  • A $\left[\mathrm{Zn}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{2}\right]^{2+}$
  • B $\left[\mathrm{Co}(\mathrm{en})_{3}\right]^{3+}$
  • C $\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}(\mathrm{en})\right]^{3+}$
  • D $\left[\mathrm{Zn}(\mathrm{en})_{2}\right]^{2+}$
    (en $=$ ethylenediamine)
Solution:
1442 Upvotes Verified Answer
The correct answer is: $\left[\mathrm{Co}(\mathrm{en})_{3}\right]^{3+}$
Option (b) shows optical isomerism $\left[\mathrm{Co}(\mathrm{en})_{3}\right]^{3+}$


Complexes of $\mathrm{Zn}^{++}$cannot show optical isomerism as they are tetrahedral complexes with plane of symmetry.
$\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}(\mathrm{en})\right]^{3+}$ have two planes of symmetry hence it is also optically inactive. $\left[\mathrm{Zn}(\mathrm{en})_{2}\right]^{2+}$ cannot show optical isomerism

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