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Which one of the following has maximumnumber of unpaired electrons?
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The correct answer is:
$\mathrm{Fe}^{2+}$
$\mathrm{Mg}^{2+}=1 \mathrm{~s}^{2}, 2 \mathrm{~s}^{2}, 2 \mathrm{p}^{6}$ (No unpaired electrons)
$\mathrm{Ti}^{3+}=1 \mathrm{~s}^{2}, 2 \mathrm{~s}^{2}, 2 \mathrm{p}^{6}, 3 \mathrm{~s}^{2}, 3 \mathrm{p}^{6}, 4 \mathrm{~s}^{0}, 3 \mathrm{~d}^{1}$ (One unpaired electrons)
$\mathrm{V}^{3+}=1 \mathrm{~s}^{2}, 2 \mathrm{~s}^{2}, 2 \mathrm{p}^{6}, 3 \mathrm{~s}^{2}, 3 \mathrm{p}^{6}, 4 \mathrm{~s}^{0}, 3 \mathrm{~d}^{2}$ (Two unpaired electrons)
$\mathrm{Fe}^{2+}=1 \mathrm{~s}^{2}, 2 \mathrm{~s}^{2}, 2 \mathrm{p}^{6}, 3 \mathrm{~s}^{2}, 3 \mathrm{p}^{6}, 4 \mathrm{~s}^{0}, 3 \mathrm{~d}^{6}$ (Four unpaired electrons)
$\therefore \mathrm{Fe}^{2+}$ has highest number of unpaired electrons.
$\mathrm{Ti}^{3+}=1 \mathrm{~s}^{2}, 2 \mathrm{~s}^{2}, 2 \mathrm{p}^{6}, 3 \mathrm{~s}^{2}, 3 \mathrm{p}^{6}, 4 \mathrm{~s}^{0}, 3 \mathrm{~d}^{1}$ (One unpaired electrons)
$\mathrm{V}^{3+}=1 \mathrm{~s}^{2}, 2 \mathrm{~s}^{2}, 2 \mathrm{p}^{6}, 3 \mathrm{~s}^{2}, 3 \mathrm{p}^{6}, 4 \mathrm{~s}^{0}, 3 \mathrm{~d}^{2}$ (Two unpaired electrons)
$\mathrm{Fe}^{2+}=1 \mathrm{~s}^{2}, 2 \mathrm{~s}^{2}, 2 \mathrm{p}^{6}, 3 \mathrm{~s}^{2}, 3 \mathrm{p}^{6}, 4 \mathrm{~s}^{0}, 3 \mathrm{~d}^{6}$ (Four unpaired electrons)
$\therefore \mathrm{Fe}^{2+}$ has highest number of unpaired electrons.
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