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Which one of the following lanthanide ions does not exhibit paramagnetism?
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The correct answer is:
$\mathrm{Lu}^{3+}$
Generally, paramagnetism is shown by lanthanoid ions. The paramagnetism arises due to presence of unpaired electrons in $f$-orbital.
$\mathrm{Lu}^{3+}\left(4 f^{14}\right)$ does not have unpaired electrons.
Hence, it does not exhibit paramagnetism.
$\mathrm{Lu}^{3+}\left(4 f^{14}\right)$ does not have unpaired electrons.
Hence, it does not exhibit paramagnetism.
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