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Which one of the following options is correct?
Options:
Solution:
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Verified Answer
The correct answer is:
$\tan ^{2} 30^{\circ}, \tan ^{2} 45^{\circ}, \tan ^{2} 60^{\circ}$ are in GP
Three numbers a, b and c will be in G.P. if $b^{2}=a c$. Only option (d) i.e. $\tan ^{2} 30^{\circ}, \tan ^{2} 45^{\circ}$ and $\tan ^{2} 60^{\circ}$ are
in GP.
$\because \quad \tan ^{2} 30^{\circ}=\frac{1}{3}$
$\tan ^{2} 45^{\circ}=1$
and $\tan ^{2} 60^{\circ}=3$
$\tan ^{2} 30^{\circ}, \tan ^{2} 45^{\circ}$ and $\tan ^{2} 60^{\circ}$ are in G.P.
in GP.
$\because \quad \tan ^{2} 30^{\circ}=\frac{1}{3}$
$\tan ^{2} 45^{\circ}=1$
and $\tan ^{2} 60^{\circ}=3$
$\tan ^{2} 30^{\circ}, \tan ^{2} 45^{\circ}$ and $\tan ^{2} 60^{\circ}$ are in G.P.
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