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Which one of the following statements is true for the speed $v$ and the acceleration $a$ of particle executing simple harmonic motion?
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Verified Answer
The correct answer is:
When $v$ is maximum $a$ is zero
In SHM
$\text {Velocity }=A \omega \sin \left(\omega t+\frac{\pi}{2}\right)$
Acceleration $= A \omega^2 \sin (\omega t+\pi)$
This shows that $V$ is max then $a=0$
$\text {Velocity }=A \omega \sin \left(\omega t+\frac{\pi}{2}\right)$
Acceleration $= A \omega^2 \sin (\omega t+\pi)$
This shows that $V$ is max then $a=0$
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