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Which one of the following transition metal ions is diamagnetic?
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The correct answer is:
$\mathrm{Zn}^{2+}$
Transition metal ion having absence of unpaired electron is diamagnetic.
(1) $\mathrm{Co}^{2+}=[\mathrm{Ar}] 3 d^7$ (three unpaired electrons)
(2) $\mathrm{Ni}^{2+}=[\mathrm{Ar}] 3 d^8$ (two unpaired electrons)
(3) $\mathrm{Cu}^{2+}=[\mathrm{Ar}] 3 d^9$ (one unpaired electron)
(4) $\mathrm{Zn}^{2+}=[\mathrm{Ar}] 3 d^{10}$ (no unpaired electron)
Thus, $\mathrm{Zn}^{2+}$ is diamagnetic.
(1) $\mathrm{Co}^{2+}=[\mathrm{Ar}] 3 d^7$ (three unpaired electrons)
(2) $\mathrm{Ni}^{2+}=[\mathrm{Ar}] 3 d^8$ (two unpaired electrons)
(3) $\mathrm{Cu}^{2+}=[\mathrm{Ar}] 3 d^9$ (one unpaired electron)
(4) $\mathrm{Zn}^{2+}=[\mathrm{Ar}] 3 d^{10}$ (no unpaired electron)
Thus, $\mathrm{Zn}^{2+}$ is diamagnetic.
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