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Why does \(\mathrm{NH}_3\) form hydrogen bond but \(\mathrm{PH}_3\) does not?
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Nitrogen has an electronegativity value \(3.0\), which is much higher than that of \(\mathrm{H}(2 \cdot 1)\). As a result, \(\mathrm{N}-\mathrm{H}\) bond is quite polar and hence \(\mathrm{NH}_3\) undergoes intermolecular \(\mathrm{H}\) - bonding.

Phosphorus have an electronegativity value \(2 \cdot 1\). Thus, \(\mathrm{P}-\mathrm{H}\) bond is not polar and hence \(\mathrm{PH}_3\) does not undergo \(\mathrm{H}\) - bonding.

Phosphorus have an electronegativity value \(2 \cdot 1\). Thus, \(\mathrm{P}-\mathrm{H}\) bond is not polar and hence \(\mathrm{PH}_3\) does not undergo \(\mathrm{H}\) - bonding.
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