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Question: Answered & Verified by Expert
Width of the principal maximum on a screen at a distance of 50 cm from the slit having width 0.02 cm is 312.5×10-3 cm . If waves were incident normally on the slit, then wavelength of the light from the source will be
PhysicsWave OpticsJEE Main
Options:
  • A 6000 
  • B 6250 
  • C 6400 
  • D 6525 
Solution:
1825 Upvotes Verified Answer
The correct answer is: 6250 
Width of central max. =2 λDa

λ=0.2×10-2×312.5×10-3×10-22×12m

=6250×10-10 m=6250 

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