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Question: Answered & Verified by Expert
Wires 1 and 2 carrying currents $i_1$ and $i_2$ respectively are inclined at an angle $\theta$ to each other. What is the force on a small element dl of wire 2 at a distance of $\mathrm{r}$ from wire 1 (as shown in the figure) due to the magnetic field of wire 1 ?

PhysicsMagnetic Effects of CurrentJEE MainJEE Main 2002
Options:
  • A
    $\frac{\mu_0}{2 \pi r} i_1 i_2 d l \tan \theta$
  • B
    $\frac{\mu_0}{2 \pi \mathrm{r}} \mathrm{i}_1 \mathrm{i}_2 \mathrm{~dl} \sin \theta$
  • C
    $\frac{\mu_0}{2 \pi \mathrm{r}} \mathrm{i}_1 \mathrm{i}_2 \mathrm{dl} \cos \theta$
  • D
    $\frac{\mu_0}{4 \pi r} i_1 i_2 d l \sin \theta$
Solution:
2439 Upvotes Verified Answer
The correct answer is:
$\frac{\mu_0}{2 \pi \mathrm{r}} \mathrm{i}_1 \mathrm{i}_2 \mathrm{dl} \cos \theta$
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