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Question: Answered & Verified by Expert
Work done by a Carnot engine operating between temperatures 127°C and 27°C is 2 kJ. The amount of heat transferred to the engine by the reservoir is:
PhysicsThermodynamicsJEE MainJEE Main 2023 (08 Apr Shift 2)
Options:
  • A 8 kJ
  • B 2.67 kJ
  • C 2 kJ
  • D 4 kJ
Solution:
1509 Upvotes Verified Answer
The correct answer is: 8 kJ

The temperatures in Kelvin scales are 

T2=27 °C+273=300 KT1=127 °C+273=400 K

The efficiency of the Carnot engine is

 η=1-T2T1=1-300400=14
Using the relation, η=WQ
2 kJQ=14Q=8 kJ

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