Work done in increasing the size of a soap bubble from radius of ( 3 to 5 ) cm is nearly (surface tension of soap solution = 0 . 03 Nm - 1 )

Question

Work done in increasing the size of a soap bubble from radius of ( 3 to 5 ) cm is nearly (surface tension of soap solution = 0 . 03 Nm - 1 ), 0 . 2 π mJ, 2 π mJ, 0 . 4 π mJ, 4 π mJ

MARKS App · Accepted Answer

Work done = Change in surface energy r 2 = 5 cm r 1 = 3 cm ⇒ W = 2 T × 4 π r 2 2 - r 1 2 = 2 × 0 . 03 × 4 π 5 2 - 3 2 × 10 - 4 = 0 . 4 π mJ

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