Search any question & find its solution
Question:
Answered & Verified by Expert
Write the isomers of the compound having formula \(\mathrm{C}_4 \mathrm{H}_9 \mathrm{Br}\).
Solution:
1426 Upvotes
Verified Answer
Double bond equivalent (DBE) for \(\mathrm{C}_4 \mathrm{H}_9 \mathrm{Br}\)
\(=\frac{4(4-2)+9(1-2)+1(1-2)}{2}+1=0\)
So none of the isomer has a ring or unsaturation, so the isomers are position or chain isomers
(i) \(\underset{\text{1-Bromobutane}}{\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{Br}}\)
\(=\frac{4(4-2)+9(1-2)+1(1-2)}{2}+1=0\)
So none of the isomer has a ring or unsaturation, so the isomers are position or chain isomers
(i) \(\underset{\text{1-Bromobutane}}{\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{Br}}\)
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.