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$\int(x-a)\left(x^{n-1}+x^{n-2} a+\ldots . .+a^{n-1}\right) d x=$ (where $C$ is a constant of integration)
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The correct answer is:
$\frac{x^{n+1}}{n+1}-a^n x+C$
$\begin{aligned} & \int(x-a)\left(x^{n-1}+x^{n-2} \cdot a+\ldots \ldots+a^{n-1}\right) d x \\ & =\int\left(x^n-a^n\right) d x \\ & =\frac{x^{n+1}}{n+1}-a^n x+c\end{aligned}$
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