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Question: Answered & Verified by Expert
XCl2excess+YCl2→XCl4+Y↓
YO → >  400 o C Δ 1 2 O 2 +Y , Ore of Y would be
ChemistryGeneral Principles and Processes of Isolation of MetalsJEE Main
Options:
  • A Siderite
  • B Cinnabar
  • C Malachite
  • D Hornsilver
Solution:
1889 Upvotes Verified Answer
The correct answer is: Cinnabar
The reaction sequence is as follows
SnCl2(XCl2)+HgCl2(YCl2)→SnCl4(XCl4)+Hg(Y)
HgO → >  400 o C Δ Hg +  1 2 O 2
HgS→Cinnabar

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