Xenon hexafluoride on partial hydrolysis produces compounds ${\mathrm{XeOF}}_4$​ and ${\mathrm{XeO}}_2{\mathrm{F}}_2$. In the compounds, ${\mathrm{XeOF}}_{4 }$and ${\mathrm{XeO}}_2{\mathrm{F}}_2$​, the oxidation states of Xe are +6 and +6 respectively.

${\mathrm{XeF}}_6 + {\mathrm{H}}_2\mathrm{O} \to {\mathrm{XeOF}}_{4 }+ 2\mathrm{HF}$

${\mathrm{XeOF}}_4 + {\mathrm{H}}_2\mathrm{O} \to {\mathrm{XeO}}_2{\mathrm{F}}_{2 }+ 2\mathrm{HF}$