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Young's modulus of the material of a wire is $Y$. If it is under a stress $S$, the energy stored per unit volume is given by
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2229 Upvotes
Verified Answer
The correct answer is:
$\frac{1}{2} \frac{S^{2}}{Y}$
Here $u=\frac{1}{2}$ stress $\times$ strain
also $Y=$ stress $/$ strain
Hence
$$
\begin{array}{l}
u=\frac{1}{2}(\text { stress })^{2} / Y \\
u=\frac{1}{2} \frac{S^{2}}{Y}
\end{array}
$$
also $Y=$ stress $/$ strain
Hence
$$
\begin{array}{l}
u=\frac{1}{2}(\text { stress })^{2} / Y \\
u=\frac{1}{2} \frac{S^{2}}{Y}
\end{array}
$$
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