Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Zirconium phosphate [Zr3(PO4)4] dissociates into three zirconium cations of charge​ +4 and four phosphate anions of charge -3. If molar solubility of zirconium phosphate is denoted by S and its solubility product by Ksp then which of the following relationship between S and Ksp is correct ​?
ChemistryIonic EquilibriumJEE Main
Options:
  • A S = K sp / 6 9 1 2 7
  • B S = K sp / 1 4 4 1 / 7
  • C S = K sp / 6 9 1 2 1 / 7
  • D S = K sp / 6 9 1 2 1 / 7
Solution:
1842 Upvotes Verified Answer
The correct answer is: S = K sp / 6 9 1 2 1 / 7
In the saturated solution of

Zr 3 PO 4 4 + aq 3 Zr 4 + 3 S molar + 4 PO 4 3 - 4 S molar

K sp = Zr 4 + 3 PO 4 3 - 4 = 3 S 3 4 S 4

= 2 7 × 2 5 6 × s 7 = 6 9 1 2   S 7

S = K sp 6 9 1 2 1 / 7

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.