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$\int_0^{10 \pi}|\sin x| d x$ is
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18
18
$\int_0^{10 \pi}|\sin x| d x=10\left[\int_0^{\pi / 2} \sin x d x+\int_{\pi / 2}^\pi \sin x d x\right]$
$=10 \times[\cos x]_0^{\pi / 2}+[\cos x]_{\pi / 2}^\pi ; \quad 10[1+1]=10 \times 2=20$
$=10 \times[\cos x]_0^{\pi / 2}+[\cos x]_{\pi / 2}^\pi ; \quad 10[1+1]=10 \times 2=20$
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