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$\int_0^{b-c} f^{\prime}(x+a) d x=$
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Verified Answer
The correct answer is:
$f^{\prime}(b-c+a)-f^{\prime}(a)$
$\int_0^{b-c} f^{\prime}(x+a) d x=\left[f^{\prime}(x+a)\right]_0^{b-c}=f^{\prime}(b-c+a)-f^{\prime}(a)$
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