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Question: Answered & Verified by Expert
$\int_0^{b-c} f^{\prime}(x+a) d x=$
MathematicsDefinite IntegrationJEE Main
Options:
  • A $f^{\prime}(a)-f^{\prime}(b)$
  • B $f^{\prime}(b-c+a)-f^{\prime}(a)$
  • C $f^{\prime}(b+c-a)+f^{\prime}(a)$
  • D None of these
Solution:
2352 Upvotes Verified Answer
The correct answer is: $f^{\prime}(b-c+a)-f^{\prime}(a)$
$\int_0^{b-c} f^{\prime}(x+a) d x=\left[f^{\prime}(x+a)\right]_0^{b-c}=f^{\prime}(b-c+a)-f^{\prime}(a)$

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