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0.001 mole of $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{NO}_3\right)\left(\mathrm{SO}_4\right)\right]$ was passed through a cation exchanger and the acid coming out of it required 20 mL of 0.1 M NaOH for neutralisation. Thus, the complex is
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$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{NO}_3\right)\right] \mathrm{SO}_4$
Millimoles of acid required for neutralisation
$\begin{aligned} & =20 \times 0.1=2 \text { millimoles } \\ & =0.002 \text { moles }\end{aligned}$
If 0.001 mole is neutralising 0.002 moles of base, thus, 0.001 mole of base remains unreacted. Hence, acid coming out should be basic.
$\begin{aligned} & {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{NO}_3\right)\right] \mathrm{SO}_4 \longrightarrow} \\ & {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{NO}_3\right]^{2+}+\mathrm{SO}_4^{2-}\right.}\end{aligned}$
$\begin{aligned} & =20 \times 0.1=2 \text { millimoles } \\ & =0.002 \text { moles }\end{aligned}$
If 0.001 mole is neutralising 0.002 moles of base, thus, 0.001 mole of base remains unreacted. Hence, acid coming out should be basic.
$\begin{aligned} & {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{NO}_3\right)\right] \mathrm{SO}_4 \longrightarrow} \\ & {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{NO}_3\right]^{2+}+\mathrm{SO}_4^{2-}\right.}\end{aligned}$
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